A counterexample to a conjecture of Schwartz
In 1990, motivated by applications in the social sciences, Thomas Schwartz made a conjecture about tournaments which would have had numerous attractive consequences. In particular, it implied that there is no tournament with a partition A, B of its vertex set, such that every transitive subset of A is in the out-neighbour set of some vertex in B, and vice versa. But in fact there is such a tournament, as we show in this article, and so Schwartz’ conjecture is false. Our proof is non-constructive and uses the probabilistic method. Copyright Springer-Verlag 2013
Year of publication: |
2013
|
---|---|
Authors: | Brandt, Felix ; Chudnovsky, Maria ; Kim, Ilhee ; Liu, Gaku ; Norin, Sergey ; Scott, Alex ; Seymour, Paul ; Thomassé, Stephan |
Published in: |
Social Choice and Welfare. - Springer. - Vol. 40.2013, 3, p. 739-743
|
Publisher: |
Springer |
Saved in:
Online Resource
Saved in favorites
Similar items by person
-
A counterexample to a conjecture of Schwartz
Brandt, Felix, (2013)
-
A counterexample to a conjecture of Schwartz
Brandt, Felix, (2013)
-
Submodular functions and perfect graphs
Abrishami, Tara, (2025)
- More ...